RCOOH xrightarrow{ } RCH_2OH. This mode of re | vedclass

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Question

(D) The reduction of a carboxylic acid $(RCOOH)$ to a primary alcohol $(RCH_2OH)$ requires a strong reducing agent.$LiAlH_4$ (Lithium aluminium hydrid

Vedclass · Accepted Answer

$LiAlH_4$

Vedclass · Answer

(D) The reduction of a carboxylic acid $(RCOOH)$ to a primary alcohol $(RCH_2OH)$ requires a strong reducing agent.$LiAlH_4$ (Lithium aluminium hydride) is a powerful reducing agent capable of reducing carboxylic acids directly to primary alcohols.Other reagents like $Zn/HCl$ (Clemmensen reduction) reduce carbonyl groups to methylene groups,and $Na/	ext{alcohol}$ (Bouveault-Blanc reduction) is typically used for esters.Therefore,the correct option is $(D)$.

$RCOOH \xrightarrow{ } RCH_2OH$. This mode of reduction of an acid to alcohol can be effected only by:

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