Identify the compound (B) in the following re | vedclass

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(C) $1$. The starting material is $2	ext{-formylmethylbenzoic acid}$.$2$. $NaBH_4$ is a selective reducing agent that reduces the aldehyde group $(-C

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Dihydroisocoumarin

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(C) $1$. The starting material is $2	ext{-formylmethylbenzoic acid}$.$2$. $NaBH_4$ is a selective reducing agent that reduces the aldehyde group $(-CHO)$ to a primary alcohol $(-CH_2OH)$ but does not reduce the carboxylic acid group $(-COOH)$. Thus,$(A)$ is $2	ext{-(2-hydroxyethyl)benzoic acid}$.$3$. Upon treatment with $H^{\oplus}$ and heating $(\Delta)$,the carboxylic acid and the primary alcohol undergo an intramolecular esterification (cyclization) reaction,eliminating a water molecule to form a cyclic ester known as a lactone.$4$. The product $(B)$ is $3,4	ext{-dihydroisocoumarin}$ (also known as dihydroisocoumarin).

Identify the compound $(B)$ in the following reaction sequence:
$2\text{-formylmethylbenzoic acid}$ $\xrightarrow{NaBH_4} (A)$ $\xrightarrow{H^{\oplus}, \Delta} (B) \text{ (Cyclic)}$

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Identify the compound $(B)$ in the following reaction sequence:$2\text{-formylmethylbenzoic acid}$ $\xrightarrow{NaBH_4} (A)$ $\xrightarrow{H^{\oplus}, \Delta} (B) \text{ (Cyclic)}$