vec{A} is a vector quantity such that |vec{A} | vedclass

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(C) Given that $|\vec{A}| = c$,where $c$ is a nonzero constant.The cross product of any vector with itself is defined as $\vec{A} 	imes \vec{A} = |\v

Vedclass · Accepted Answer

$\vec{A} 	imes \vec{A} = 0$

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(C) Given that $|\vec{A}| = c$,where $c$ is a nonzero constant.The cross product of any vector with itself is defined as $\vec{A} 	imes \vec{A} = |\vec{A}| |\vec{A}| \sin(	heta) \hat{n}$,where $	heta$ is the angle between the vector and itself.Since the angle between a vector and itself is $0^{\circ}$,we have $	heta = 0^{\circ}$.Substituting this into the formula: $\vec{A} 	imes \vec{A} = |\vec{A}|^2 \sin(0^{\circ}) \hat{n}$.Since $\sin(0^{\circ}) = 0$,the expression becomes $\vec{A} 	imes \vec{A} = 0$.

$\vec{A}$ is a vector quantity such that $|\vec{A}| =$ nonzero constant. Which of the following expressions is true for $\vec{A}$?

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