The $KE$ of a body is increased by $44 \%$. What is the percentage increase in its momentum?

$A$ particle of mass $m_1$ is moving with a velocity $v_1$ and another particle of mass $m_2$ is moving with a velocity $v_2$. Both of them have the same momentum,but their kinetic energies are $E_1$ and $E_2$ respectively. If $m_1 > m_2$,then:

$A$ particle is released freely from a height $H$. At a certain height,its kinetic energy is two times its potential energy. Then,the height and the speed of the particle at that instant are respectively ($g=$ acceleration due to gravity).

The momentum of a body is increased by $50 \%$. The percentage increase in the kinetic energy of the body is $...........\,\%$

Two bodies of masses $1 \ g$ and $4 \ g$ are moving with the same kinetic energy. What is the ratio of their linear momenta?

The kinetic energy possessed by a body of mass $m$ moving with a velocity $v$ is equal to $\frac{1}{2}mv^2$,provided