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(A) In the Calvin cycle,the fixation of one molecule of $CO_2$ requires $3\,ATP$ and $2\,NADPH$ molecules.For the fixation of three $CO_2$ molecules,t

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$9\,ATP, 6\,NADPH$

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(A) In the Calvin cycle,the fixation of one molecule of $CO_2$ requires $3\,ATP$ and $2\,NADPH$ molecules.For the fixation of three $CO_2$ molecules,the calculation is as follows:$ATP$ required = $3 	imes 3 = 9\,ATP$$NADPH$ required = $3 	imes 2 = 6\,NADPH$Therefore,to fix three $CO_2$ molecules,$9\,ATP$ and $6\,NADPH$ are required.

How many $ATP$ and $NADPH$ molecules are required for the fixation of three $CO_2$ molecules in the Calvin cycle?

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