$(S1) (p \Rightarrow q) \vee (p \wedge (\sim q))$ is a tautology. $(S2) ((\sim p) \Rightarrow (\sim q)) \wedge ((\sim p) \vee q)$ is a contradiction. Then
- Aonly $(S2)$ is correct
- Bboth $(S1)$ and $(S2)$ are correct
- Cboth $(S1)$ and $(S2)$ are wrong
- Donly $(S1)$ is correct
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$p \Rightarrow q$ can also be written as
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