$MgSO_4$ on reaction with $NH_4OH$ and $Na_2HPO_4$ forms a white crystalline precipitate. What is its formula?
- A$Mg(NH_4)PO_4$
- B$Mg_3(PO_4)_2$
- C$MgCl_2 \cdot MgSO_4$
- D$MgSO_4$
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Similar Questions
Which reagent is used in the qualitative analysis of Group $IV$ cations?
Medium
View SolutionMatch the List-$I$ with List-$II$ :
Cations Group reaction $P \rightarrow Pb^{2+}, Cu^{2+}$ $(i)$ $H_2S$ gas in presence of dilute $HCl$ $Q \rightarrow Al^{3+}, Fe^{3+}$ $(ii)$ $(NH_4)_2CO_3$ in presence of $NH_4OH$ $R \rightarrow Co^{2+}, Ni^{2+}$ $(iii)$ $NH_4OH$ in presence of $NH_4Cl$ $S \rightarrow Ba^{2+}, Ca^{2+}$ $(iv)$ $H_2S$ in presence of $NH_4OH$
| Cations | Group reaction |
| $P \rightarrow Pb^{2+}, Cu^{2+}$ | $(i)$ $H_2S$ gas in presence of dilute $HCl$ |
| $Q \rightarrow Al^{3+}, Fe^{3+}$ | $(ii)$ $(NH_4)_2CO_3$ in presence of $NH_4OH$ |
| $R \rightarrow Co^{2+}, Ni^{2+}$ | $(iii)$ $NH_4OH$ in presence of $NH_4Cl$ |
| $S \rightarrow Ba^{2+}, Ca^{2+}$ | $(iv)$ $H_2S$ in presence of $NH_4OH$ |
In qualitative analysis,in order to detect $II$ group basic radicals,$H_2S$ gas is passed in the presence of dilute $HCl$ to:
Difficult
View SolutionMatch List-$I$ with List-$II$ and select the correct answer using the codes given below.
List-$I$ (Ion involved) List-$II$ (Agent) $(i) \, Ni^{2+}$ $(A).$ Sodium thiosulphate $(ii) \, Ag^{+}$ $(B).$ Sodium nitroprusside $(iii) \, Cu^{2+}$ $(C).$ Ammonia $(iv) \, S^{2-}$ $(D).$ Dimethylglyoxime
| List-$I$ (Ion involved) | List-$II$ (Agent) |
| $(i) \, Ni^{2+}$ | $(A).$ Sodium thiosulphate |
| $(ii) \, Ag^{+}$ | $(B).$ Sodium nitroprusside |
| $(iii) \, Cu^{2+}$ | $(C).$ Ammonia |
| $(iv) \, S^{2-}$ | $(D).$ Dimethylglyoxime |
The distinguishing reagent between silver and lead salts is:
Difficult
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