$\left| {(1 + i)\frac{{(2 + i)}}{{(3 + i)}}} \right| = $
- A$-\frac{1}{2}$
- B$\frac{1}{2}$
- C$1$
- D$-1$
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Similar Questions
If $Z_1$ and $Z_2$ are conjugate complex numbers, match the items in Column-$I$ with Column-$II$:
Column-$I$ Column-$II$ $A. Z_1 Z_2$ $1. \text{imaginary axis}$ $B. Z_1 + Z_2 = 0$ $2. \text{Im}(-Z_2)$ $C. \text{Im}(Z_1)$ $3. |Z_1|^2$ $D. \text{Re}(Z_1)$ $4. \text{Re}(Z_2)$
| Column-$I$ | Column-$II$ |
| $A. Z_1 Z_2$ | $1. \text{imaginary axis}$ |
| $B. Z_1 + Z_2 = 0$ | $2. \text{Im}(-Z_2)$ |
| $C. \text{Im}(Z_1)$ | $3. |Z_1|^2$ |
| $D. \text{Re}(Z_1)$ | $4. \text{Re}(Z_2)$ |
If $\left|z+\frac{2}{z}\right|=2$,then the maximum value of $|z|$ is
The value of $|z - 5|$ if $z = x + iy$ is:
Medium
View SolutionIf $z$ is a complex number,then $(\overline {{z^{ - 1}}} )(\overline z ) = $
Easy
View Solution$A$ real value of $x$ will satisfy the equation $\left(\frac{3-4ix}{3+4ix}\right) = \alpha - i\beta$ (where $\alpha, \beta$ are real),if
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