$A$ particle is released from height $S$ above the surface of the earth. At a certain height,its kinetic energy is three times its potential energy. The height from the surface of the earth and the speed of the particle at that instant are respectively:

  • A
    $\frac{S}{2}, \sqrt{\frac{3gS}{2}}$
  • B
    $\frac{S}{2}, \frac{3gS}{2}$
  • C
    $\frac{S}{4}, \frac{3gS}{2}$
  • D
    $\frac{S}{4}, \sqrt{\frac{3gS}{2}}$

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