A solenoid with an air core has length 48 pi | vedclass

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(C) The formula for the self-inductance $L$ of a solenoid is given by $L = \frac{\mu_0 N^2 A}{\ell}$.Given values are:Length $\ell = 48 \pi \ cm = 48

Vedclass · Accepted Answer

$1.44$

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(C) The formula for the self-inductance $L$ of a solenoid is given by $L = \frac{\mu_0 N^2 A}{\ell}$.Given values are:Length $\ell = 48 \pi \ cm = 48 \pi 	imes 10^{-2} \ m$Area $A = 12 \ cm^2 = 12 	imes 10^{-4} \ m^2$Number of turns $N = 1200$Permeability of free space $\mu_0 = 4 \pi 	imes 10^{-7} \ T \cdot m/A$Substituting these values into the formula:$L = \frac{(4 \pi 	imes 10^{-7}) 	imes (1200)^2 	imes (12 	imes 10^{-4})}{48 \pi 	imes 10^{-2}}$$L = \frac{4 \pi 	imes 10^{-7} 	imes 1440000 	imes 12 	imes 10^{-4}}{48 \pi 	imes 10^{-2}}$$L = \frac{4 \pi 	imes 1.44 	imes 10^6 	imes 10^{-7} 	imes 12 	imes 10^{-4}}{48 \pi 	imes 10^{-2}}$$L = \frac{48 \pi 	imes 1.44 	imes 10^{-5}}{48 \pi 	imes 10^{-2}}$$L = 1.44 	imes 10^{-3} \ H = 1.44 \ mH$.

$A$ solenoid with an air core has length $48 \pi \ cm$,area of cross section $12 \ cm^2$ and $1200$ turns. The self-inductance of the solenoid is: (in $mH$)

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