A compound microscope consists of an objectiv | vedclass

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Question

(A) For the eyepiece:Given $v_e = -25 \ cm$ (final image at least distance of distinct vision),$f_e = 6.25 \ cm$.Using the lens formula $\frac{1}{v_e}

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$-2.5$

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(A) For the eyepiece:Given $v_e = -25 \ cm$ (final image at least distance of distinct vision),$f_e = 6.25 \ cm$.Using the lens formula $\frac{1}{v_e} - \frac{1}{u_e} = \frac{1}{f_e}$:$\frac{1}{-25} - \frac{1}{u_e} = \frac{1}{6.25} \implies -\frac{1}{u_e} = \frac{1}{6.25} + \frac{1}{25} = \frac{4+1}{25} = \frac{5}{25} = \frac{1}{5}$.So,$u_e = -5 \ cm$.The distance between the lenses is $L = 15 \ cm$,so the image distance for the objective lens is $v_o = L - |u_e| = 15 - 5 = 10 \ cm$.For the objective lens:$v_o = 10 \ cm$,$f_o = 2 \ cm$.Using the lens formula $\frac{1}{v_o} - \frac{1}{u_o} = \frac{1}{f_o}$:$\frac{1}{10} - \frac{1}{u_o} = \frac{1}{2} \implies -\frac{1}{u_o} = \frac{1}{2} - \frac{1}{10} = \frac{5-1}{10} = \frac{4}{10} = \frac{2}{5}$.Therefore,$u_o = -2.5 \ cm$.The object should be placed $2.5 \ cm$ in front of the objective lens.

Similar Questions

Explain the difference between the functions of a telescope and a microscope.

$A$ simple microscope is used to see an object first in blue light and then in red light. Due to the change from blue to red light, what is the effect on its magnifying power?

The least distance of distinct vision is $25 \, cm$. The magnifying power of a simple microscope with a focal length of $5 \, cm$ is:

The focal length of the objective and eye lens of a microscope are $4 \, cm$ and $8 \, cm$ respectively. If the least distance of distinct vision is $24 \, cm$ and the object distance is $4.5 \, cm$ from the objective lens, then the magnifying power of the microscope will be:

The focal length of the objective and eye lens of a microscope are $4 \ cm$ and $8 \ cm$ respectively. If the least distance of distinct vision is $24 \ cm$ and the object distance is $4.5 \ cm$ from the objective lens,then the magnifying power of the microscope will be: (Final image is at infinity)

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