$V_1 \ \text{c.c.}$ of a solution having molarity $M_1$ is diluted to have molarity $M_2$. The volume of water required to be added will be $:-$
- A$(\frac{M_1-M_2}{M_2}) V_1$
- B$(\frac{M_1-M_2}{M_1}) V_1$
- C$(\frac{M_1}{M_2-M_1}) V_1$
- D$(\frac{M_2}{M_2-M_1}) V_1$
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