Molality of an aqueous solution of urea is 4. | vedclass

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(C) Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent.Given $m = 4.44 \ m$,this means $4.44 \ mol$ of urea is dissolv

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(C) Molality $(m)$ is defined as the number of moles of solute per kilogram of solvent.Given $m = 4.44 \ m$,this means $4.44 \ mol$ of urea is dissolved in $1000 \ g$ $(1 \ kg)$ of water.Moles of water $(n_{water})$ = $\frac{1000 \ g}{18 \ g/mol} \approx 55.56 \ mol$.Mole fraction of urea $(X_{urea})$ = $\frac{n_{urea}}{n_{urea} + n_{water}} = \frac{4.44}{4.44 + 55.56} = \frac{4.44}{60} = 0.074$.We are given $X_{urea} = x 	imes 10^{-5}$.$0.074 = 7400 	imes 10^{-5}$.Therefore,$x = 7400$.

Molality of an aqueous solution of urea is $4.44 \ m$. Mole fraction of urea in solution is $x \times 10^{-5}$. Value of $x$ is. . . . . . (integer answer)

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