(B) The reaction is $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g).$ The reaction quotient $Q_P$ is given by the expression: $Q_P = \frac{(P_{NH_3})^2}

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(B) The reaction is $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g).$ The reaction quotient $Q_P$ is given by the expression: $Q_P = \frac{(P_{NH_3})^2}{(P_{N_2})(P_{H_2})^3}.$ Substituting the given partial pressures: $Q_P = \frac{(3)^2}{(1)(2)^3} = \frac{9}{8} = 1.125 \ atm^{-2}.$ Comparing $Q_P$ with $K_P$: $Q_P = 1.125$ and $K_P = 4.28 \times 10^{-5}.$ Since $Q_P > K_P,$ the reaction will proceed in the backward direction to reach equilibrium.

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Mix Examples- 6-1.Equilibrium (Chemical Equilibrium)

Medium

$A$ reaction mixture containing $H_2, N_2$ and $NH_3$ has partial pressures of $2 \ atm, 1 \ atm$ and $3 \ atm$ respectively at $725 \ K.$ If the value of $K_P$ for the reaction,$N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$ is $4.28 \times 10^{-5} \ atm^{-2}$ at $725 \ K,$ in which direction will the net reaction proceed?

A
Forward
B
Backward
C
No net reaction
D
Direction of reaction cannot be predicted

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6-1.Equilibrium (Chemical Equilibrium)

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Mix Examples- 6-1.Equilibrium (Chemical Equilibrium)

At $717 \ K$,$3.2 \ mol$ of $HI$ is heated in a closed tube. $20\%$ of $HI$ decomposes at equilibrium according to the reaction $2HI_{(g)} \rightleftharpoons H_{2_{(g)}} + I_{2_{(g)}}$. Find $K_c$ and the moles of $HI$,$H_2$,and $I_2$ at equilibrium.

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Solid $NH_4HS$ is placed in a flask containing $NH_3$ gas at a certain temperature and a pressure of $0.50 \ atm$. The $NH_4HS$ decomposes to form $NH_3$ gas and $H_2S$ gas. When equilibrium is established in the flask,the total pressure increases to $0.84 \ atm$. What is the equilibrium constant $(K_p)$ for the decomposition of $NH_4HS$ at this temperature?

Medium

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For the complete dissociation of an aqueous solution of $A_2B_3$ according to the reaction $A_2B_3 \rightarrow 2A^{3+} + 3B^{2-}$,the number of $A^{3+}$ ions is equal to:

Medium

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$N_2O_{4(g)}$ at $300 \ K$ is kept in a closed container under $1 \ atm$. At equilibrium,$20\%$ of $N_2O_{4(g)}$ is converted to $NO_{2(g)}$.
$N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$
Hence,the resultant pressure is: (in $atm$)

Medium

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At $T \ K$,$K_c$ for the reaction $AO_{2(g)} + BO_{2(g)} \rightleftharpoons AO_{3(g)} + BO_{(g)}$ is $16$. One mole each of reactants and products are taken in a $1 \ L$ flask and heated to $T \ K$,and equilibrium is established. What is the equilibrium concentration of $BO$ (in $mol \ L^{-1}$)?

MediumTS EAMCET 2024

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At $717 \ K$,$3.2 \ mol$ of $HI$ is heated in a closed tube. $20\%$ of $HI$ decomposes at equilibrium according to the reaction $2HI_{(g)} \rightleftharpoons H_{2_{(g)}} + I_{2_{(g)}}$. Find $K_c$ and the moles of $HI$,$H_2$,and $I_2$ at equilibrium.

For the complete dissociation of an aqueous solution of $A_2B_3$ according to the reaction $A_2B_3 \rightarrow 2A^{3+} + 3B^{2-}$,the number of $A^{3+}$ ions is equal to:

$N_2O_{4(g)}$ at $300 \ K$ is kept in a closed container under $1 \ atm$. At equilibrium,$20\%$ of $N_2O_{4(g)}$ is converted to $NO_{2(g)}$.$N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$Hence,the resultant pressure is: (in $atm$)

At $T \ K$,$K_c$ for the reaction $AO_{2(g)} + BO_{2(g)} \rightleftharpoons AO_{3(g)} + BO_{(g)}$ is $16$. One mole each of reactants and products are taken in a $1 \ L$ flask and heated to $T \ K$,and equilibrium is established. What is the equilibrium concentration of $BO$ (in $mol \ L^{-1}$)?

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$N_2O_{4(g)}$ at $300 \ K$ is kept in a closed container under $1 \ atm$. At equilibrium,$20\%$ of $N_2O_{4(g)}$ is converted to $NO_{2(g)}$.
$N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$
Hence,the resultant pressure is: (in $atm$)