$A$ conductivity cell dipped in $0.05 \ M$ $KCl$ has a resistance of $600 \ \Omega$. If the conductivity is $0.0015 \ \Omega^{-1} \ cm^{-1}$,what is the value of the cell constant (in $cm^{-1}$)?
- A$0.47$
- B$0.90$
- C$1.5$
- D$2.5$
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Similar Questions
The equivalent conductances of $CH_3COONa$,$HCl$,and $CH_3COOH$ at infinite dilution are $91$,$426$,and $391 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. What is the equivalent conductance of $NaCl$ at infinite dilution?
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View SolutionWhich among the following is the $CORRECT$ formula for the determination of cell constant?
Given below are two statements:
Assertion $(A)$: Conductivity of an electrolyte decreases on dilution.
Reason $(R)$: On dilution,the number of ions per unit volume increases.
The correct answer is:
Assertion $(A)$: Conductivity of an electrolyte decreases on dilution.
Reason $(R)$: On dilution,the number of ions per unit volume increases.
The correct answer is:
If the resistivity of a $0.8 \ M \ KCl$ solution is $2.5 \times 10^{-3} \ \Omega \ cm$,calculate the molar conductivity of the solution.
The limiting molar conductivities $(\Lambda_0)$ for $NaCl$,$KBr$ and $KCl$ are $126$,$152$ and $150 \ S \ cm^2 \ mol^{-1}$ respectively. What is the $\Lambda_0$ of $NaBr$?
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