If the resistivity of a $0.8 \ M \ KCl$ solution is $2.5 \times 10^{-3} \ \Omega \ cm$,calculate the molar conductivity of the solution.

  • A
    $3 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$
  • B
    $2 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$
  • C
    $4 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$
  • D
    $5 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$

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