Calculate the molar conductivity of $0.2 \text{ M}$ $KCl$ solution at $298 \text{ K}$ if the conductivity $(k)$ is $0.0248 \text{ } \Omega^{-1} \text{cm}^{-1}$.

Resistance of $0.1\, M\, KCl$ solution in a conductance cell is $300\, \Omega$ and conductivity is $0.013\, S\, cm^{-1}$. The value of cell constant is

The molar conductivity of a $0.02 \ M$ solution of an electrolyte is $124 \times 10^{-4} \ S \ m^2 \ mol^{-1}$. What is the resistance of the same solution (in ohms),kept in a cell with a cell constant of $129 \ m^{-1}$?

How can the ionic conductivity of an unknown solution be determined?

For a salt $XY$, which is a strong electrolyte, the plot of $\Lambda_m$ versus $\sqrt{C}$ has a slope of $-90.0 \ S \ cm^2 \ mol^{3/2} \ L^{1/2}$ at $298 \ K$. At $0.01 \ M$ concentration of $XY$, the value of $\Lambda_m$ is $145.5 \ S \ cm^2 \ mol^{-1}$. The limiting molar conductivity of $Y^-$ ion ($\lambda^\circ_{Y^-}$, in $S \ cm^2 \ mol^{-1}$) at $298 \ K$ will be (Given $\lambda^\circ_{X^+} = 74.0 \ S \ cm^2 \ mol^{-1}$) (in $.0$)

The equivalent conductance at infinite dilution of a weak acid such as $HF$: