34.2 g of sugar is dissolved in 1.8 times 10 | vedclass

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Question

(A) Given: Mass of sugar $= 34.2 \ g$,Molar mass of sugar $= 342 \ g/mol$. Number of moles of sugar $(n_{sugar}) = \frac{34.2}{342} = 0.1 \ mol$. Mass

Vedclass · Accepted Answer

$0.0099$

Vedclass · Answer

(A) Given: Mass of sugar $= 34.2 \ g$,Molar mass of sugar $= 342 \ g/mol$. Number of moles of sugar $(n_{sugar}) = \frac{34.2}{342} = 0.1 \ mol$. Mass of water $= 1.8 	imes 10^{2} \ g = 180 \ g$,Molar mass of water $= 18 \ g/mol$. Number of moles of water $(n_{water}) = \frac{180}{18} = 10 \ mol$. Mole fraction of sugar $(x_{sugar}) = \frac{n_{sugar}}{n_{sugar} + n_{water}} = \frac{0.1}{0.1 + 10} = \frac{0.1}{10.1} \approx 0.0099$.

$34.2 \ g$ of sugar is dissolved in $1.8 \times 10^{2} \ g$ of water to form sugar syrup. Calculate the mole fraction of sugar. (Molar mass of sugar $= 342 \ g/mol$,water $= 18 \ g/mol$)

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