(A) The work done during expansion is given by the formula $W = -P_{ext} \Delta V$. Since the gas expands,work is done by the system,so $W = -5 \ bar

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(A) The work done during expansion is given by the formula $W = -P_{ext} \Delta V$. Since the gas expands,work is done by the system,so $W = -5 \ bar \ dm^3$. Given $P_{ext} = 2.5 \ bar$,$V_2 = 4.5 \ L$,and $V_1 = x \ L$. Since $1 \ L = 1 \ dm^3$,we have: $-5 \ bar \ dm^3 = -2.5 \ bar \times (4.5 \ L - x \ L)$. Dividing both sides by $-2.5 \ bar$: $2 = 4.5 - x$. Rearranging for $x$: $x = 4.5 - 2 = 2.5 \ L$.

Class 11 Chemistry Thermodynamics Basic concepts

Medium

$A$ gas is allowed to expand against a constant external pressure of $2.5 \ bar$ from an initial volume '$x$' $L$ to a final volume of $4.5 \ L$. If the amount of work done is $5 \ dm^3 \ bar$,what is the value of '$x$' (in $L$)?

MHT CET 2021 All MHT CET

A
$2.5$
B
$4.5$
C
$6.0$
D
$1.2$

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$A$ gas is allowed to expand against a constant external pressure of $2.5 \ bar$ from an initial volume '$x$' $L$ to a final volume of $4.5 \ L$. If the amount of work done is $5 \ dm^3 \ bar$,what is the value of '$x$' (in $L$)?

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