$\tan 3A \cdot \tan 2A \cdot \tan A = $

  • A
    $\tan 3A + \tan 2A - \tan A$
  • B
    $\tan 3A - \tan 2A - \tan A$
  • C
    $\tan 3A + \tan 2A + \tan A$
  • D
    $\tan 3A - \tan 2A + \tan A$

Explore More

Similar Questions

यदि $\cos A = \frac{7}{25}$ और $\frac{3 \pi}{2} < A < 2 \pi$ है,तो $\cos \frac{A}{4} + \cos \frac{A}{2} - \cos 2A =$

$\cos ^4 \frac{\pi}{8}+\cos ^4 \frac{3 \pi}{8}+\cos ^4 \frac{5 \pi}{8}+\cos ^4 \frac{7 \pi}{8}=$

$\frac{\sec 8A - 1}{\sec 4A - 1} = $

यदि $\tan \alpha = \frac{1}{7}$ और $\sin \beta = \frac{1}{\sqrt{10}}$ जहाँ $0 < \alpha, \beta < \frac{\pi}{2}$ है,तो $2\beta$ का मान ज्ञात कीजिए।

यदि $\tan \theta = \frac{a}{b}$ है,तो $b \cos 2 \theta + a \sin 2 \theta = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo