A step-up transformer has 300 turns of primar | vedclass

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(A) Given that,number of turns in primary winding,$N_{p} = 300$.Number of turns in secondary winding,$N_{s} = 450$.Primary voltage,$V_{p} = 150 \ V$.P

Vedclass · Accepted Answer

$6.0 \ A, 225 \ V$

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(A) Given that,number of turns in primary winding,$N_{p} = 300$.Number of turns in secondary winding,$N_{s} = 450$.Primary voltage,$V_{p} = 150 \ V$.Primary current,$I_{p} = 9 \ A$.For a transformer,the relationship between voltage and turns is given by $\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}}$.Substituting the values: $\frac{V_{s}}{150} = \frac{450}{300}$.$\Rightarrow V_{s} = \frac{450}{300} 	imes 150 = 1.5 	imes 150 = 225 \ V$.Assuming an ideal transformer,the power input equals the power output: $V_{p} I_{p} = V_{s} I_{s}$.Substituting the values: $150 	imes 9 = 225 	imes I_{s}$.$\Rightarrow I_{s} = \frac{1350}{225} = 6.0 \ A$.Thus,the secondary current is $6.0 \ A$ and the secondary voltage is $225 \ V$.

$A$ step-up transformer has $300$ turns of primary winding and $450$ turns of secondary winding. The primary is connected to $150 \ V$ and the current flowing through it is $9 \ A$. The current and voltage in the secondary are:

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