An AC source of internal resistance 10^3 Omeg | vedclass

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(B) For maximum power transfer,the load resistance $R_L$ must be matched to the source resistance $R_s$ through the transformer.The effective resistan

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$10: 1$

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(B) For maximum power transfer,the load resistance $R_L$ must be matched to the source resistance $R_s$ through the transformer.The effective resistance $R'$ seen by the source is given by $R' = (N_p/N_s)^2 R_L$,where $N_p$ is the number of turns in the primary and $N_s$ is the number of turns in the secondary.For impedance matching,we set $R' = R_s$.Given $R_s = 10^3 \Omega$ and $R_L = 10 \Omega$,we have:$10^3 = (N_p/N_s)^2 	imes 10$$(N_p/N_s)^2 = 10^3 / 10 = 100$$N_p/N_s = \sqrt{100} = 10$Therefore,the ratio $N_p : N_s$ is $10 : 1$.

An $AC$ source of internal resistance $10^3 \Omega$ is connected to a transformer. The ratio of the number of turns in the primary to the number of turns in the secondary to match the source to a load resistance of $10 \Omega$ is

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