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(D) Given:Primary turns $N_{1} = 100$Secondary turns $N_{2} = 200$Input current $I_{1} = 10 \ A$Input voltage $V_{1} = 220 \ V$For an ideal transforme

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$5.0$

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(D) Given:Primary turns $N_{1} = 100$Secondary turns $N_{2} = 200$Input current $I_{1} = 10 \ A$Input voltage $V_{1} = 220 \ V$For an ideal transformer,the power input equals the power output: $V_{1}I_{1} = V_{2}I_{2}$.Also,the transformer ratio is given by $\frac{N_{2}}{N_{1}} = \frac{V_{2}}{V_{1}} = \frac{I_{1}}{I_{2}}$.Using the current relation: $\frac{N_{2}}{N_{1}} = \frac{I_{1}}{I_{2}}$.Substituting the values: $\frac{200}{100} = \frac{10}{I_{2}}$.$2 = \frac{10}{I_{2}}$.$I_{2} = \frac{10}{2} = 5.0 \ A$.

If the primary coil of a transformer has $100$ turns and the secondary has $200$ turns,then for an input of $220 \ V$ at $10 \ A$,the output current in the step-up transformer will be . . . . . . . (in $A$)

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