In a step-up transformer, the turn ratio is 1 | vedclass

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(B) Given: Turn ratio $\frac{N_p}{N_s} = \frac{1}{10}$, Secondary resistance $R_s = 200 \, \Omega$, Secondary current $I_s = 0.5 \, A$.First, calculat

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$10 \, V, 5 \, A$

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(B) Given: Turn ratio $\frac{N_p}{N_s} = \frac{1}{10}$, Secondary resistance $R_s = 200 \, \Omega$, Secondary current $I_s = 0.5 \, A$.First, calculate the secondary voltage $(V_s)$ using Ohm's law:$V_s = I_s 	imes R_s = 0.5 \, A 	imes 200 \, \Omega = 100 \, V$.Using the transformer ratio formula $\frac{V_s}{V_p} = \frac{N_s}{N_p}$:$\frac{100}{V_p} = \frac{10}{1} \implies V_p = 10 \, V$.Using the current relation $\frac{I_p}{I_s} = \frac{N_s}{N_p}$:$\frac{I_p}{0.5} = \frac{10}{1} \implies I_p = 5 \, A$.Thus, the primary voltage is $10 \, V$ and the primary current is $5 \, A$.

In a step-up transformer, the turn ratio is $1:10$. A resistance of $200 \, \Omega$ connected across the secondary is drawing a current of $0.5 \, A$. What is the primary voltage and current?

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