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(A) According to the law of conservation of linear momentum,since the bomb is initially at rest,the total initial momentum is zero. Therefore,the tota

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$\sqrt{13} p$

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(A) According to the law of conservation of linear momentum,since the bomb is initially at rest,the total initial momentum is zero. Therefore,the total final momentum must also be zero.Let the momentum of the third part be $\vec{p}_3$.$\vec{p}_1 + \vec{p}_2 + \vec{p}_3 = 0$$(-3 p \hat{i}) + (2 p \hat{j}) + \vec{p}_3 = 0$$\vec{p}_3 = 3 p \hat{i} - 2 p \hat{j}$The magnitude of the momentum of the third part is:$|\vec{p}_3| = \sqrt{(3p)^2 + (-2p)^2}$$|\vec{p}_3| = \sqrt{9p^2 + 4p^2}$$|\vec{p}_3| = \sqrt{13} p$

$A$ bomb at rest explodes into $3$ parts of the same mass. The momentum of two parts is $-3 p \hat{i}$ and $2 p \hat{j}$ respectively. The magnitude of the momentum of the third part is

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