A carrier wave of peak voltage 16 text{ V} is | vedclass

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(D) The modulation index $(m_a)$ is defined as the ratio of the peak voltage of the modulating signal $(V_m)$ to the peak voltage of the carrier wave

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$12$

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(D) The modulation index $(m_a)$ is defined as the ratio of the peak voltage of the modulating signal $(V_m)$ to the peak voltage of the carrier wave $(V_c)$.Formula: $m_a = \frac{V_m}{V_c}$Given:Peak voltage of carrier wave $(V_c)$ = $16 	ext{ V}$Modulation index $(m_a)$ = $75 \% = 0.75$Calculation:$V_m = m_a 	imes V_c$$V_m = 0.75 	imes 16 	ext{ V}$$V_m = 12 	ext{ V}$Therefore, the peak voltage of the modulating signal is $12 	ext{ V}$.

$A$ carrier wave of peak voltage $16 \text{ V}$ is used to transmit a signal. If the modulation index is $75 \%$, the peak voltage of the modulating signal is (in $\text{ V}$)

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$A$ carrier wave of peak voltage $15 \,V$ is used to transmit a message signal. If the modulation index is $60 \%$, then the peak voltage of the modulating signal is (in $\,V$)

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