$A$ galvanometer of resistance $50 \Omega$ is converted to an ammeter. After shunting,the effective resistance of the ammeter is $2.5 \Omega$. The value of the shunt is

  • A
    $\frac{100}{19} \Omega$
  • B
    $\frac{50}{19} \Omega$
  • C
    $\frac{25}{19} \Omega$
  • D
    $\frac{75}{19} \Omega$

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