What is the function of the spiral spring in the construction of a galvanometer?

  • A
    To provide a restoring torque.
  • B
    To increase the magnetic field.
  • C
    To decrease the resistance of the coil.
  • D
    To support the weight of the coil.

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Similar Questions

In a circuit for finding the resistance of a galvanometer by the half-deflection method,a $6\,V$ battery and a high resistance of $11\,k\Omega$ are used. The figure of merit of the galvanometer is $60\,\mu A/\text{division}$. In the absence of shunt resistance,the galvanometer produces a deflection of $\theta = 9$ divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of $\theta/2$ is closest to .................. $\Omega$.

$A$ galvanometer of resistance $50 \Omega$ is connected to a battery of $3 \text{ V}$ along with a resistance of $2950 \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $20$ divisions,the resistance in series should be: (in $\Omega$)

$A$ galvanometer has a resistance of $50 \ \Omega$ and it allows a maximum current of $5 \ mA$. It can be converted into a voltmeter to measure up to $100 \ V$ by connecting in series a resistor of resistance: (in $\Omega$)

$A$ galvanometer coil has a resistance of $15\; \Omega$ and the meter shows full-scale deflection for a current of $4\; mA$. How will you convert the meter into an ammeter of range $0$ to $6\; A$?

“By increasing current sensitivity,voltage sensitivity is also increased”. This statement is true or false.

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