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(B) The magnetic force acting on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force is always perpendicular to the v

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its momentum changes but its kinetic energy remains constant

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(B) The magnetic force acting on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Since the force is always perpendicular to the velocity vector $\vec{v}$,the work done by the magnetic force is $W = \int \vec{F} \cdot d\vec{r} = \int \vec{F} \cdot \vec{v} dt = 0$.According to the work-energy theorem,the change in kinetic energy is equal to the work done,so the kinetic energy remains constant.However,because the direction of the velocity vector changes continuously during the motion,the momentum $\vec{p} = m\vec{v}$ changes.Therefore,the momentum changes while the kinetic energy remains constant.

$A$ charged particle moves through a magnetic field perpendicular to its direction. Then

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