A solenoid having 400 turns per metre has a c | vedclass

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(D) The magnetic intensity $H$ is given by $H = nI$,where $n$ is the number of turns per unit length and $I$ is the current.Given $n = 400 \ m^{-1}$ a

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$8 	imes 10^4$

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(D) The magnetic intensity $H$ is given by $H = nI$,where $n$ is the number of turns per unit length and $I$ is the current.Given $n = 400 \ m^{-1}$ and $I = 0.5 \ A$,we have $H = 400 	imes 0.5 = 200 \ Am^{-1}$.The relationship between relative permeability $\mu_r$ and magnetic susceptibility $\chi$ is $\mu_r = 1 + \chi$,so $\chi = \mu_r - 1$.Given $\mu_r = 400$,we find $\chi = 400 - 1 = 399$.The magnetization $M$ is given by $M = \chi H$.Substituting the values,$M = 399 	imes 200 = 79800 \ Am^{-1}$.This is approximately $8 	imes 10^4 \ Am^{-1}$.

$A$ solenoid having $400$ turns per metre has a core of a material with relative permeability $400$. When a current of $0.5 \ A$ is passed through it,the magnetization of the core material in $Am^{-1}$ is nearly

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