$A$ liquid rises to a height of $2.4 \ cm$ in a glass capillary $P$. Another glass capillary $Q$ having a diameter $80\%$ of capillary $P$ is immersed in the same liquid. The rise of liquid in capillary $Q$ is (in $cm$)

Water rises to a height of $2 \,cm$ in a capillary tube. If the cross-sectional area of the tube is reduced to $\frac{1}{16}^{\text{th}}$ of the initial area, then water will rise to a height of: (in $\,cm$)

Water rises to a height of $16.3 \, cm$ in a capillary tube of height $18 \, cm$ above the water level. If the tube is cut at a height of $12 \, cm$ above the water level,then:

When one end of a capillary tube is dipped in water,the height of the water column is $h$. The upward force of $108 \ dyne$ due to surface tension is balanced by the force due to the weight of the water column. What is the inner circumference of the capillary (in $cm$)? (Surface tension of water $T = 7.2 \times 10^{-2} \ N/m$)

When a capillary tube of radius '$r$' is immersed in water, the rise of water is up to height '$h$'. The mass of water in the capillary tube is '$m$'. When another capillary tube of radius '$xr$' is immersed in water, the mass of water that will rise in this tube is:

$A$ capillary tube,when immersed vertically in a liquid,records a rise of $3 \, cm$. If the tube is immersed in the liquid at an angle of ${60^\circ}$ with the vertical,what is the length of the liquid column along the tube in $cm$?