(A) Given mass $m = 5 \ kg$ and displacement $x = t^3 - 2t - 10$.Velocity $v$ is the derivative of displacement with respect to time:$v = \frac{dx}{dt

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Given mass $m = 5 \ kg$ and displacement $x = t^3 - 2t - 10$.Velocity $v$ is the derivative of displacement with respect to time:$v = \frac{dx}{dt} = \frac{d}{dt}(t^3 - 2t - 10) = 3t^2 - 2$.Acceleration $a$ is the derivative of velocity with respect to time:$a = \frac{dv}{dt} = \frac{d}{dt}(3t^2 - 2) = 6t$.Force $F$ is given by Newton's second law,$F = ma$:$F = 5 \times (6t) = 30t$.At $t = 5 \ s$:$F = 30 \times 5 = 150 \ N$.

Class 11 Physics Newton's Laws of Motion and Friction Second Law of Motion

Easy

$A$ body of mass $5 \ kg$ is moving in a straight line. The relation between its displacement and time is $x = (t^3 - 2t - 10) \ m$. What is the force acting on it at the end of $5 \ s$ (in $N$)?

MHT CET 2020 All MHT CET

A
$150$
B
$120$
C
$80$
D
$100$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Newton's Laws of Motion and Friction

Subtopic

Second Law of Motion

Previous Year

MHT CET 2020 Paper All MHT CET years →

$A$ cricketer catches a ball of mass $150\; g$ in $0.1\; s$ moving with a speed of $20\; m/s$. The force experienced by the cricketer is ..... $N$.

Difficult

View Solution

Which physical quantity is represented by the first derivative of linear momentum with respect to time?

Easy

View Solution

$A$ force vector applied on a mass is represented as $\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k} \, N$ and it accelerates with $1 \, m/s^2$. What will be the mass of the body?

Difficult

View Solution

The average resisting force that must act on a $5 \,kg$ mass to reduce its speed from $65 \,cm/s$ to $15 \,cm/s$ in $0.2 \,s$ is .......... $N$.

Medium

View Solution

$A$ body of $5 \, kg$ is moving with a velocity of $20 \, m/s$. If a force of $100 \, N$ is applied on it for $10 \, s$ in the same direction as its velocity,what will be the final velocity of the body in $m/s$?

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ body of mass $5 \ kg$ is moving in a straight line. The relation between its displacement and time is $x = (t^3 - 2t - 10) \ m$. What is the force acting on it at the end of $5 \ s$ (in $N$)?

Similar Questions

$A$ cricketer catches a ball of mass $150\; g$ in $0.1\; s$ moving with a speed of $20\; m/s$. The force experienced by the cricketer is ..... $N$.

Which physical quantity is represented by the first derivative of linear momentum with respect to time?

$A$ force vector applied on a mass is represented as $\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k} \, N$ and it accelerates with $1 \, m/s^2$. What will be the mass of the body?

The average resisting force that must act on a $5 \,kg$ mass to reduce its speed from $65 \,cm/s$ to $15 \,cm/s$ in $0.2 \,s$ is .......... $N$.

$A$ body of $5 \, kg$ is moving with a velocity of $20 \, m/s$. If a force of $100 \, N$ is applied on it for $10 \, s$ in the same direction as its velocity,what will be the final velocity of the body in $m/s$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module