A driver applies the brakes on seeing the red | vedclass

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(A) Given: Initial velocity $u = 15 ~m/s$,acceleration $a = -0.3 ~m/s^2$,time $t = 60 ~s$. First,we calculate the time taken to stop: $v = u + at \imp

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$25$

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(A) Given: Initial velocity $u = 15 ~m/s$,acceleration $a = -0.3 ~m/s^2$,time $t = 60 ~s$. First,we calculate the time taken to stop: $v = u + at \implies 0 = 15 - 0.3t \implies t = 50 ~s$. Since the driver applies brakes for $60 ~s$,the vehicle stops at $t = 50 ~s$ and remains at rest for the remaining $10 ~s$. Distance covered in $50 ~s$: $s = ut + \frac{1}{2}at^2 = 15(50) + \frac{1}{2}(-0.3)(50)^2 = 750 - 375 = 375 ~m$. Distance from the traffic light $= 400 ~m - 375 ~m = 25 ~m$.

$A$ driver applies the brakes on seeing the red traffic signal $400 ~m$ ahead. At the time of applying the brakes,the vehicle was moving with $15 ~m/s$ and retarding at $0.3 ~m/s^2$. The distance covered by the vehicle from the traffic light $1$ minute after the application of brakes is (in $~m$)

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