(B) The acceleration $a$ of a particle in $S.H.M.$ is given by $a = \omega^2 x$,where $x$ is the displacement.Given $a = 0.5 \,m/s^2$ and $x = 0.02 \,

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The acceleration $a$ of a particle in $S.H.M.$ is given by $a = \omega^2 x$,where $x$ is the displacement.Given $a = 0.5 \,m/s^2$ and $x = 0.02 \,m$.$\omega^2 = \frac{a}{x} = \frac{0.5}{0.02} = 25 \,rad^2/s^2$.Taking the square root,we get $\omega = 5 \,rad/s$.The maximum velocity $V_{\max}$ is given by $V_{\max} = A \omega$,where $A$ is the amplitude.Given $A = 0.1 \,m$.$V_{\max} = 0.1 \times 5 = 0.5 \,m/s$.

Class 11 Physics Oscillations Velocity of Simple Harmonic Motion

Easy

$A$ particle performing linear $S.H.M.$ of amplitude $0.1 \,m$ has displacement $0.02 \,m$ and acceleration $0.5 \,m/s^2$. The maximum velocity of the particle in $m/s$ is

MHT CET 2021 All MHT CET

A
$0.05$
B
$0.5$
C
$0.01$
D
$0.25$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Oscillations

Subtopic

Velocity of Simple Harmonic Motion

Previous Year

MHT CET 2021 Paper All MHT CET years →

The time period of a particle in simple harmonic motion is $8 \ s$. At $t=0$, it is at the mean position. The ratio of the distances travelled by it in the first and second seconds is

DifficultAP EAMCET 2012

View Solution

$A$ particle executes $S.H.M.$ and its position varies with time as $x = A \sin \omega t$. Its average speed during its motion from mean position to mid-point of mean and extreme position is

Medium

View Solution

The displacement of a body executing $SHM$ is given by $x = A \sin (2\pi t + \pi /3).$ The first time from $t = 0$ when the velocity is maximum is .... $\sec$

Medium

View Solution

For a particle executing $S.H.M.$ having amplitude $A$,the speed of the particle is $\left(\frac{1}{3}\right)^{rd}$ of its maximum speed when the displacement from the mean position is

MediumMHT CET 2024

View Solution

The graph in the figure represents:

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ particle performing linear $S.H.M.$ of amplitude $0.1 \,m$ has displacement $0.02 \,m$ and acceleration $0.5 \,m/s^2$. The maximum velocity of the particle in $m/s$ is

Similar Questions

The time period of a particle in simple harmonic motion is $8 \ s$. At $t=0$, it is at the mean position. The ratio of the distances travelled by it in the first and second seconds is

$A$ particle executes $S.H.M.$ and its position varies with time as $x = A \sin \omega t$. Its average speed during its motion from mean position to mid-point of mean and extreme position is

The displacement of a body executing $SHM$ is given by $x = A \sin (2\pi t + \pi /3).$ The first time from $t = 0$ when the velocity is maximum is .... $\sec$

For a particle executing $S.H.M.$ having amplitude $A$,the speed of the particle is $\left(\frac{1}{3}\right)^{rd}$ of its maximum speed when the displacement from the mean position is

The graph in the figure represents:

Vedclass Test Series

Exam Paper Generator

Online Exam Module