$A$ thin prism $P_{1}$ with angle $4^{\circ}$ and made from glass of refractive index $1.54$ is combined with another thin prism $P_{2}$ made from glass of refractive index $1.72$ to produce dispersion without deviation. The angle of prism for $P_{2}$ is (in $^{\circ}$)

The respective angles of the flint and crown glass prisms are $A'$ and $A$. They are to be used for dispersion without deviation. The ratio of their angles $A'/A$ will be:

It was found that the refractive index of the material of a certain prism varied as $\mu = 1.5 + 0.004 / \lambda^{2}$,where $\lambda$ is the wavelength of light used to measure the refractive index. The same material was then used to construct a thin prism of apex angle $10^{\circ}$. Angles of minimum deviation $\delta_{m}$ of the prism were recorded for the sources with wavelengths $\lambda_{1}$ and $\lambda_{2}$,respectively. Then,

The angles of incidence and emergence of a light ray passing through a prism of angle $A$ are $i$ and $e$ respectively. The total deviation produced by the prism is

Obtain the relation between incidence angle,emergence angle,prism angle,and deviation angle for refraction through a prism.

For a small angled prism with prism angle $A$,the angle of minimum deviation $(\delta_m)$ varies with the refractive index $(\mu)$ of the prism as shown in the graph.