A glass cube of length 24 cm has a small air | vedclass

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Question

(A) Let $x$ be the real depth of the air bubble from the first face.When viewed from the first face,the apparent depth is given by $d_1 = \frac{x}{\mu

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(A) Let $x$ be the real depth of the air bubble from the first face.When viewed from the first face,the apparent depth is given by $d_1 = \frac{x}{\mu} = 10 \ cm$.So,$x = 10\mu$.When viewed from the opposite face,the real depth of the bubble is $(24 - x)$.The apparent depth is given by $d_2 = \frac{24 - x}{\mu} = 6 \ cm$.So,$24 - x = 6\mu$.Substituting $x = 10\mu$ into the second equation:$24 - 10\mu = 6\mu$$24 = 16\mu$$\mu = \frac{24}{16} = 1.5$.Therefore,the refractive index of glass is $1.5$.

$A$ glass cube of length $24 \ cm$ has a small air bubble trapped inside. When viewed normally from one face,it is $10 \ cm$ below the surface. When viewed normally from the opposite face,its apparent distance is $6 \ cm$. The refractive index of glass is:

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