(A) The relationship between torque $(\tau)$ and the change in angular momentum $(\Delta L)$ is given by the angular impulse-momentum theorem: $\Delta

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(A) The relationship between torque $(\tau)$ and the change in angular momentum $(\Delta L)$ is given by the angular impulse-momentum theorem: $\Delta L = \int \tau dt$. Since the torque is constant, the change in angular momentum is simply the product of torque and time: $\Delta L = \tau \times \Delta t$. Given: Torque $(\tau)$ = $200 \, N-m$ Time $(\Delta t)$ = $4 \, s$ Calculation: $\Delta L = 200 \, N-m \times 4 \, s = 800 \, kg-m^{2}/s$. Therefore, the change in angular momentum is $800 \, kg-m^{2}/s$.

Class 11 Physics System of Particles and Rotational Motion Angular Momentum and Angular Impulse

Medium

$A$ constant torque of $200 \, N-m$ turns a flywheel, which is at rest, about an axis through its centre and perpendicular to its plane. If its moment of inertia is $50 \, kg-m^{2}$, then in $4 \, s$, what will be the change in its angular momentum?

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A
$800 \, kg-m^{2}/s$
B
$200 \, kg-m^{2}/s$
C
$40 \, kg-m^{2}/s$
D
$20 \, kg-m^{2}/s$

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System of Particles and Rotational Motion

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Angular Momentum and Angular Impulse

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$A$ constant torque of $200 \, N-m$ turns a flywheel, which is at rest, about an axis through its centre and perpendicular to its plane. If its moment of inertia is $50 \, kg-m^{2}$, then in $4 \, s$, what will be the change in its angular momentum?

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