$A$ body slides down a smooth inclined plane of inclination $\theta$ and reaches the bottom with velocity $V$. If the same body is a ring which rolls down the same inclined plane,then the linear velocity at the bottom of the plane is:

  • A
    $\frac{V}{\sqrt{2}}$
  • B
    $V$
  • C
    $2V$
  • D
    $\frac{V}{2}$

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