A flywheel at rest is to reach an angular vel | vedclass

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(D) Given: Initial angular velocity $\omega_0 = 0 \ rad \ s^{-1}$,final angular velocity $\omega = 24 \ rad \ s^{-1}$,and time $t = 8 \ s$.First,calcu

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$96$

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(D) Given: Initial angular velocity $\omega_0 = 0 \ rad \ s^{-1}$,final angular velocity $\omega = 24 \ rad \ s^{-1}$,and time $t = 8 \ s$.First,calculate the constant angular acceleration $\alpha$ using the formula $\alpha = \frac{\omega - \omega_0}{t}$.$\alpha = \frac{24 - 0}{8} = 3 \ rad \ s^{-2}$.Now,calculate the total angle $	heta$ turned through using the kinematic equation $	heta = \omega_0 t + \frac{1}{2} \alpha t^2$.$	heta = 0 	imes 8 + \frac{1}{2} 	imes 3 	imes (8)^2$.$	heta = \frac{1}{2} 	imes 3 	imes 64 = 3 	imes 32 = 96 \ rad$.

$A$ flywheel at rest is to reach an angular velocity of $24 \ rad \ s^{-1}$ in $8 \ s$ with constant angular acceleration. The total angle turned through during this interval is (in $rad$)

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