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(B) In uniform circular motion,the centripetal acceleration $a_c$ is given by the formula $a_c = \omega^2 r$,where $\omega$ is the angular velocity an

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(B) In uniform circular motion,the centripetal acceleration $a_c$ is given by the formula $a_c = \omega^2 r$,where $\omega$ is the angular velocity and $r$ is the radius of the circular path.Since angular velocity $\omega = 2 \pi f$,where $f$ is the frequency,we can substitute this into the acceleration formula:$a_c = (2 \pi f)^2 r = 4 \pi^2 f^2 r$.From this expression,we can see that the acceleration is directly proportional to the square of the frequency: $a_c \propto f^2$.If the frequency $f$ is doubled $(f' = 2f)$,the new acceleration $a_c'$ becomes:$a_c' \propto (2f)^2 = 4f^2$.Therefore,the acceleration becomes $4$ times the original value.

If the frequency of an object in uniform circular motion is doubled,its acceleration becomes

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