$A$ black body has a maximum wavelength $\lambda_{m}$ at a temperature of $2200 \ K$. Its corresponding wavelength at a temperature of $3300 \ K$ will be:

The wavelength of maximum energy released during an atomic explosion was $2.93 \times 10^{-10} \, m$. The maximum temperature attained must be (Wien's constant $b = 2.93 \times 10^{-3} \, mK$).

$A$ black body at $1227\,^oC$ emits radiations with maximum intensity at a wavelength of $5000\,\mathring{A}$. If the temperature of the body is increased by $1000\,^oC$,the maximum intensity will be at ....... $\mathring{A}$.

Two bodies $A$ and $B$ of equal surface area have thermal emissivities of $0.01$ and $0.81$ respectively. The two bodies are radiating energy at the same rate. Maximum energy is radiated from the two bodies $A$ and $B$ at wavelengths $\lambda_A$ and $\lambda_B$ respectively. The difference in these two wavelengths is $1 \mu m$. If the temperature of body $A$ is $5802 \ K$, then the value of $\lambda_B$ is:

$A$ black body has a maximum wavelength $\lambda_{m}$ at a temperature of $2000 \ K$. Its corresponding wavelength at a temperature of $3000 \ K$ will be:

The wavelength of maximum intensity of radiation emitted by a star is $289.8 \, nm$. The radiation intensity of the star is (Stefan's constant $\sigma = 5.67 \times 10^{-8} \, W m^{-2} K^{-4}$, Wien's constant $b = 2898 \, \mu m K$).