(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{a}$,where $\lambda

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decreases with increase of slit width.

(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{a}$,where $\lambda$ is the wavelength of the light and $a$ is the width of the slit.From this relation,it is clear that the angular width $\theta$ is inversely proportional to the slit width $a$,i.e.,$\theta \propto \frac{1}{a}$.Therefore,as the slit width $a$ increases,the angular width of the central maximum decreases.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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A
increases with increase of slit width.
B
decreases with increase of slit width.
C
decreases with decrease of slit width.
D
may increase or decrease with decrease of slit width.

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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In a single-slit diffraction pattern,if the source of light is replaced by a source of shorter wavelength,the width of the central maximum will:

In a diffraction pattern due to a single slit of width $a$,the first minimum is observed at an angle $30^{\circ}$ when light of wavelength $5000 \; \mathring{A}$ is incident on the slit. The first secondary maximum is observed at an angle of

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$A$ parallel beam of fast-moving electrons is incident normally on a narrow slit. $A$ fluorescent screen is placed at a large distance from the slit. If the speed of the electrons is increased,which of the following statements is correct?

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