$A$ simple harmonic progressive wave is given by $Y = Y_0 \sin 2 \pi (nt - \frac{x}{\lambda})$. If the wave velocity is $(1/8)^{\text{th}}$ of the maximum particle velocity,then the wavelength is

  • A
    $\frac{\pi Y_0}{2}$
  • B
    $\frac{\pi Y_0}{4}$
  • C
    $\frac{\pi Y_0}{8}$
  • D
    $\frac{\pi Y_0}{16}$

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