A transverse wave travelling along a stretche | vedclass

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(C) The wavelength $\lambda$ of the wave is given by the formula $\lambda = \frac{v}{f}$,where $v$ is the speed and $f$ is the frequency.Substituting

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$\frac{5\pi}{3} \ radian$

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(C) The wavelength $\lambda$ of the wave is given by the formula $\lambda = \frac{v}{f}$,where $v$ is the speed and $f$ is the frequency.Substituting the given values,$\lambda = \frac{30}{250} = 0.12 \ m$.The phase difference $\Delta\phi$ between two points separated by a path difference $\Delta x$ is given by $\Delta\phi = \frac{2\pi}{\lambda} 	imes \Delta x$.Given the path difference $\Delta x = 10 \ cm = 0.1 \ m$.Substituting the values,$\Delta\phi = \frac{2\pi}{0.12} 	imes 0.1$.$\Delta\phi = \frac{0.2\pi}{0.12} = \frac{20\pi}{12} = \frac{5\pi}{3} \ radian$.

$A$ transverse wave travelling along a stretched string has a speed of $30 \ m/s$ and a frequency of $250 \ Hz$. The phase difference between two points on the string $10 \ cm$ apart at the same instant is

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