A particle at rest starts moving with a const | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that,angular acceleration $\alpha = 4 \ rad/s^2$ and initial angular velocity $\omega_0 = 0$.Centripetal (radial) acceleration is given by $

Vedclass · Accepted Answer

$1/2$

Vedclass · Answer

(C) Given that,angular acceleration $\alpha = 4 \ rad/s^2$ and initial angular velocity $\omega_0 = 0$.Centripetal (radial) acceleration is given by $a_r = r \omega^2$.Tangential acceleration is given by $a_t = r \alpha$.We are given that the magnitudes of centripetal and tangential acceleration are equal,so $a_r = a_t$.Substituting the expressions,we get $r \omega^2 = r \alpha$.Dividing both sides by $r$,we have $\omega^2 = \alpha = 4$.Taking the square root,$\omega = 2 \ rad/s$.Using the kinematic equation for rotational motion,$\omega = \omega_0 + \alpha t$.Since $\omega_0 = 0$,we have $\omega = \alpha t$.Substituting the known values,$2 = 4t$.Therefore,$t = 2/4 = 1/2 \ s$.

$A$ particle at rest starts moving with a constant angular acceleration of $4 \ rad/s^2$ in a circular path. The time at which the magnitudes of its centripetal acceleration and tangential acceleration will be equal is (in seconds):

Similar Questions

If the speed of a particle moving in a circle of radius $2 \ m$ is given as $v = 2t + 2$,then its centripetal acceleration after $1 \ s$ will be ......... $m/s^2$.

$A$ flywheel rotates with a uniform angular acceleration. Its angular velocity increases from $20\pi \, rad/s$ to $40\pi \, rad/s$ in $10 \, s$. How many rotations did it make in this period?

Angular displacement $(\theta)$ of a flywheel varies with time as $\theta = at + bt^2 + ct^3$. The angular acceleration is given by:

$A$ wheel which is initially at rest is subjected to a constant angular acceleration about its axis. It rotates through an angle of $15^{\circ}$ in time $t \ s$. The increase in angle through which it rotates in the next $2t \ s$ is (in $^{\circ}$)

The relative angular speed of the hour hand and the second hand of a clock is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module