C_6H_5OC_2H_5 + HI rightarrow X + Y. Here X a | vedclass

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Question

(A) The reaction of an alkyl aryl ether with $HI$ involves the cleavage of the $C_{alkyl}-O$ bond because the $C_{aryl}-O$ bond has partial double bon

Vedclass · Accepted Answer

$C_6H_5OH$ and $C_2H_5I$

Vedclass · Answer

(A) The reaction of an alkyl aryl ether with $HI$ involves the cleavage of the $C_{alkyl}-O$ bond because the $C_{aryl}-O$ bond has partial double bond character due to resonance and is stronger.Therefore,the reaction proceeds as follows:$C_6H_5-O-C_2H_5 + HI \rightarrow C_6H_5OH + C_2H_5I$Here,$X$ is $C_6H_5OH$ (phenol) and $Y$ is $C_2H_5I$ (ethyl iodide).Thus,the correct option is $A$.

$C_6H_5OC_2H_5 + HI \rightarrow X + Y$. Here $X$ and $Y$ are . . . . . . .

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