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Which of the following relations is correct?

If $\tan \theta = 2$ and $\theta$ lies in the third quadrant,then the value of $\sec \theta$ is

$1+\sec ^2 x \sin ^2 x=$

If $\sin A = -\frac{60}{61}$,$\cot B = -\frac{40}{9}$ and neither $A$ nor $B$ is in the $4^{\text{th}}$ quadrant,then $6 \cot A + 4 \sec B = $

$\sin 120^{\circ} \cos 150^{\circ} - \cos 240^{\circ} \sin 330^{\circ}$ is equal to :

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