A uniform wire has a resistance of 24 Omega. | vedclass

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(C) The total resistance of the wire is $R = 24 \Omega$.When the wire is bent into a circle,the diameter divides the wire into two equal semicircular

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$6$

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(C) The total resistance of the wire is $R = 24 \Omega$.When the wire is bent into a circle,the diameter divides the wire into two equal semicircular parts.The resistance of each semicircular part is $R' = \frac{R}{2} = \frac{24 \Omega}{2} = 12 \Omega$.These two semicircular parts are connected in parallel between the two points on the diameter.The equivalent resistance $R_{eq}$ is given by the formula for parallel resistors:$\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'} = \frac{1}{12} + \frac{1}{12} = \frac{2}{12} = \frac{1}{6} \Omega^{-1}$.Therefore,$R_{eq} = 6 \Omega$.

$A$ uniform wire has a resistance of $24 \Omega$. It is bent in the form of a circle. The effective resistance between the two points on any diameter of the circle is . . . . . . . (in $\Omega$)

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