A circular coil of area 2 text{ cm}^2 is plac | vedclass

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(C) The induced charge $\Delta Q$ flowing through a coil is given by the formula: $\Delta Q = \frac{\Delta \phi}{R}$.Here,$\Delta \phi$ is the change

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$1.2 	ext{ mC}$

Vedclass · Answer

(C) The induced charge $\Delta Q$ flowing through a coil is given by the formula: $\Delta Q = \frac{\Delta \phi}{R}$.Here,$\Delta \phi$ is the change in magnetic flux,$N$ is the number of turns,$A$ is the area,$B$ is the magnetic field,and $R$ is the resistance.Given: $N = 10$,$A = 2 	ext{ cm}^2 = 2 	imes 10^{-4} 	ext{ m}^2$,$B = 3 	ext{ T}$,$R = 5 	ext{ } \Omega$.The change in flux is $\Delta \phi = N \cdot A \cdot B$.Substituting the values: $\Delta Q = \frac{N \cdot A \cdot B}{R} = \frac{10 	imes 2 	imes 10^{-4} 	imes 3}{5}$.$\Delta Q = \frac{60 	imes 10^{-4}}{5} = 12 	imes 10^{-4} 	ext{ C}$.$\Delta Q = 1.2 	imes 10^{-3} 	ext{ C} = 1.2 	ext{ mC}$.

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