$A$ solenoid has a core of a material with relative permeability of $400$. The solenoid windings are insulated from the core and carry a current of $2 \text{ A}$. If the number of turns is $1000$ per meter,then the value of magnetic intensity will be . . . . . . .

  • A
    $8 \times 10^5 \text{ A m}^{-1}$
  • B
    $2 \times 10^3 \text{ A m}^{-1}$
  • C
    $2 \times 10^{-3} \text{ A m}^{-1}$
  • D
    $8 \times 10^{-5} \text{ A m}^{-1}$

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Similar Questions

$A$ winding wire which is used to frame a solenoid can bear a maximum $10\, A$ current. If the length of the solenoid is $80\, cm$ and its cross-sectional radius is $3\, cm$,then the required length of the winding wire is $(B = 0.2\, T)$.

For a long current-carrying solenoid,the magnetic field inside is $0.6 \ T$. The magnetic energy per unit volume is . . . . . . .

$A$ toroid has a number of turns per unit length $n$ and current $i$. What is the magnetic field inside the toroid?

Derive the expression for the magnetic field inside a long straight solenoid.

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$A$ coil wrapped around a toroid has an inner radius of $20 \,cm$ and an outer radius of $25 \,cm$. If the wire wrapping makes $800$ turns and carries a current of $12 \,A$, the maximum and minimum values of the magnetic field within the toroid are:

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